Lleyton Hewitt made short work of Olivier Rochus on Saturday to advance to the last 16 at Wimbledon.
The Australian dominated the opening exchanges and although Rochus rallied, Hewitt wrapped up a 6-1 6-4 6-4 success in one hour and 58 minutes on Court Two.
Rochus, at 5ft 5in the shortest player on the ATP Tour, had no answer to Hewitt’s greater weight of shot and the sixth seed now faces a fourth round contest against either David Ferrer or Fernando Gonzalez.
Hewitt, the last man to win the title in SW19 before Roger Federer, was unstoppable in the first set, grabbing two breaks to take it in 25 minutes.
The second started in the same vein.
Hewitt wasted two break points in the third game but made no mistake when he gained two more in the fifth.
The Aussie wobbled slightly when trying to serve it out, allowing Rochus the glimmer of an opportunity, but the Belgian was unable to capitalise.
An early break in the third set seemed to signal the end for Rochus but he gamely battled back to level matters at 4-4.
But Hewitt, displaying trademark grit, broke back immediately and never looked back.